The previous version of this claimed a retraction, but in fact only constructed a section. I will just construct both a section and a retraction.
From Ian Ray.
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nodes/path-objects.tex
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nodes/path-objects.tex
···
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\end{construction}
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\begin{lemma}[From edges to identifications via propositional fans]\label[lemma]{lem:edge-to-id}
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Suppose that each fan $\Fan{\gA}{x}$ of a reflexive graph $\gA$ is a proposition. Then each $\IdToEdge{\gA}[x,y]{-}$ has a retraction $\EdgeToId{\gA}[x,y]{-} \colon x\Edge{\gA}y\to \Id{\vrt{\gA}}{x}{y}$.
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Suppose that each fan $\Fan{\gA}{x}$ of a reflexive graph $\gA$ is a proposition. Then each $\IdToEdge{\gA}[x,y]{-}$ has a quasi-inverse $\EdgeToId{\gA}[x,y]{-} \colon x\Edge{\gA}y\to \Id{\vrt{\gA}}{x}{y}$.
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\end{lemma}
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\begin{proof}
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Let $\Phi_x$ be the proof that a given fan $\Fan{\gA}{x}$ is a proposition. Rather than defining $\EdgeToId{\gA}[x,y]{-} : x\Edge{\gA}y\to \Id{\vrt{\gA}}{x}{y}$ directly, we construct a slightly more general function that anticipates the contractibility of $\Fan{\gA}{x}$.
···
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}
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}
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Next we exhibit the witness of retraction.
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Next we prove that $\EdgeToId{\gA}[x,y]{-}$ is a section of $\IdToEdge{\gA}[x,y]{-}$.
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\iblock{
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\mhang{
···
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}{\Rx{\gA}{x}}
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}
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\commentrow{by reflexivity}
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}
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}
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Finally, we prove that $\EdgeToId{\gA}[x,y]{-}$ is a retraction of $\IdToEdge{\gA}[x,y]{-}$.
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\iblock{
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\mhang{
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x,y:\vrt{\gA}; p : \Id{\vrt{\gA}}{x}{y}
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\vdash \Id{\Id{\vrt{A}}{x}{y}}{\EdgeToId{\gA}[x,y]{\IdToEdge{\gA}[x,y]{p}}}{p}
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}{
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\commentrow{by identification induction}
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\mrow{
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x:\vrt{\gA} \vdash
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\Id{\Id{\vrt{A}}{x}{x}}{\EdgeToId{\gA}[x,x]{\IdToEdge{\gA}[x,x]{\Refl}}}{\Refl}
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}
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\commentrow{by definition}
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\mrow{
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x:\vrt{\gA} \vdash
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\Id{\Id{\vrt{A}}{x}{x}}{
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\EdgeToIdGen{\gA}[x,x]{
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\Rx{\gA}x
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}{
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\Phi_x\,(x,\Rx{\gA}x)\,(x,\Rx{\gA}x)
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}
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}{\Refl}
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}
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\commentrow{because $\Fan{\gA}{x}$ is a set}
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\mrow{
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x:\vrt{\gA} \vdash
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\Id{\Id{\vrt{A}}{x}{x}}{
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\EdgeToIdGen{\gA}[x,x]{
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\Rx{\gA}x
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}{
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\Refl
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}
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}{\Refl}
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}
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\commentrow{by definition}
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\mrow{
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x:\vrt{\gA} \vdash
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\Id{\Id{\vrt{A}}{x}{x}}{\Refl}{\Refl}
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}
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\commentrow{by reflexivity}
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\qedhere
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}
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}
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Lemma 41: strengthening to a quasi-inverse
The previous version of this claimed a retraction, but in fact only
constructed a section. I will just construct both a section and a
retraction.
From Ian Ray.
expand 0 comments
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